Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

MCQ Cloud

MCQ Cloud Logo MCQ Cloud Logo

MCQ Cloud Navigation

  • Discussion
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
  • Discussion
  • About Us
  • Blog
  • Contact Us

Share & grow the world's knowledge!

We want to connect the people who have knowledge to the people who need it, to bring together people with different perspectives so they can understand each other better, and to empower everyone to share their knowledge.

Create A New Account

Home

/146

Mathematic Quiz

Math quiz helps us to increase our knowledge

1 / 146

The G.C.D. of 1.08, 0.36 and 0.9 is:

Explanation:

Given numbers are 1.08, 0.36 and 0.90.   H.C.F. of 108, 36 and 90 is 18,

 H.C.F. of given numbers = 0.18.

Explanation:

Given numbers are 1.08, 0.36 and 0.90.   H.C.F. of 108, 36 and 90 is 18,

 H.C.F. of given numbers = 0.18.

2 / 146

What is the area of a triangle whose base is given to be 7 cm and height as 8 cm?

Explanation: We know that the formula for the area of a triangle is,

area = ½ x base x height

Substituting the values for the base and height, we get,

area = ½ x 7 x 3 cm2 

= 28 cm2

Explanation: We know that the formula for the area of a triangle is,

area = ½ x base x height

Substituting the values for the base and height, we get,

area = ½ x 7 x 3 cm2 

= 28 cm2

3 / 146

The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

Explanation:

Let the numbers be 2x and 3x.

Then, their L.C.M. = 6x.

So, 6x = 48 or x = 8.

 The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.

Explanation:

Let the numbers be 2x and 3x.

Then, their L.C.M. = 6x.

So, 6x = 48 or x = 8.

 The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.

4 / 146

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

Explanation:

L.C.M. of 5, 6, 4 and 3 = 60.

On dividing 2497 by 60, the remainder is 37.

 Number to be added = (60 - 37) = 23.

Explanation:

L.C.M. of 5, 6, 4 and 3 = 60.

On dividing 2497 by 60, the remainder is 37.

 Number to be added = (60 - 37) = 23.

5 / 146

42 ÷ 7 + 10 – 3

Answer

Division: 42 ÷ 7 = 6.
Expression: 6 + 10 – 3.
Left to right: 6 + 10 = 16, 16 – 3 = 13.

Answer

Division: 42 ÷ 7 = 6.
Expression: 6 + 10 – 3.
Left to right: 6 + 10 = 16, 16 – 3 = 13.

6 / 146

The product of two numbers is 120 and the sum of their squares is 289. The sum of the number is:

Explanation:

Let the numbers be x and y.

Then, xy = 120 and x2 + y2 = 289.

 (x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529

 x + y = 529 = 23.

Explanation:

Let the numbers be x and y.

Then, xy = 120 and x2 + y2 = 289.

 (x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529

 x + y = 529 = 23.

7 / 146

The number of pairs of identical faces in a cuboid.

Explanation: A cuboid comprises rectangles. Of the 6 faces, only 2 will be identical (i.e. present in pairs of l x b, b x h, h x l)

Explanation: A cuboid comprises rectangles. Of the 6 faces, only 2 will be identical (i.e. present in pairs of l x b, b x h, h x l)

8 / 146

The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is:

Let the numbers be x and y.

Then, xy = 9375 and x = 15.
y
xy = 9375
(x/y) 15

 y2 = 625.

 y = 25.

 x = 15y = (15 x 25) = 375.

 Sum of the numbers = x + y = 375 + 25 = 400.

Let the numbers be x and y.

Then, xy = 9375 and x = 15.
y
xy = 9375
(x/y) 15

 y2 = 625.

 y = 25.

 x = 15y = (15 x 25) = 375.

 Sum of the numbers = x + y = 375 + 25 = 400.

9 / 146

The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

Explanation:

Required number = H.C.F. of (1657 - 6) and (2037 - 5)

= H.C.F. of 1651 and 2032 = 127.

Explanation:

Required number = H.C.F. of (1657 - 6) and (2037 - 5)

= H.C.F. of 1651 and 2032 = 127.

10 / 146

The sum of the digits of a two-digit number is 15 and the difference between the digits is 3. What is the two-digit number?

Explanation:

Let the ten's digit be x and unit's digit be y.

Then, x + y = 15 and x - y = 3   or   y - x = 3.

Solving x + y = 15   and   x - y = 3, we get: x = 9, y = 6.

Solving x + y = 15   and   y - x = 3, we get: x = 6, y = 9.

So, the number is either 96 or 69.

Hence, the number cannot be determined.

Explanation:

Let the ten's digit be x and unit's digit be y.

Then, x + y = 15 and x - y = 3   or   y - x = 3.

Solving x + y = 15   and   x - y = 3, we get: x = 9, y = 6.

Solving x + y = 15   and   y - x = 3, we get: x = 6, y = 9.

So, the number is either 96 or 69.

Hence, the number cannot be determined.

11 / 146

Evaluate: {[(12 – 4) × 2] ÷ 4} + 3

Solution:

Parentheses: 12 – 4 = 8.
Square brackets: 8 × 2 = 16.
Curly brackets: 16 ÷ 4 = 4.
Add: 4 + 3 = 7.

Answer: 7

Solution:

Parentheses: 12 – 4 = 8.
Square brackets: 8 × 2 = 16.
Curly brackets: 16 ÷ 4 = 4.
Add: 4 + 3 = 7.

Answer: 7

12 / 146

What is the place value of 5 in the given decimal 924.75?

The correct answer is (d) hundredth.
In the decimal 924.75, the 5 is the second digit to the right of the decimal point, which represents the hundredths place (or $\frac{5}{100}$).
The correct answer is (d) hundredth.
In the decimal 924.75, the 5 is the second digit to the right of the decimal point, which represents the hundredths place (or $\frac{5}{100}$).

13 / 146

The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:

Explanation:

Greatest number of 4-digits is 9999.

L.C.M. of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399.

 Required number (9999 - 399) = 9600.

Explanation:

Greatest number of 4-digits is 9999.

L.C.M. of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399.

 Required number (9999 - 399) = 9600.

14 / 146

Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?

Explanation:

Total number of votes polled = (1136 + 7636 + 11628) = 20400.

 Required percentage = 11628 x 100 % = 57%.
20400
Explanation:

Total number of votes polled = (1136 + 7636 + 11628) = 20400.

 Required percentage = 11628 x 100 % = 57%.
20400

15 / 146

Simplify: 20 ÷ {[10 – (4 × 2)] + 3}

Solution:

Parentheses: 4 × 2 = 8.
Square brackets: 10 – 8 = 2.
Curly brackets: 2 + 3 = 5.
Divide: 20 ÷ 5 = 4.

Solution:

Parentheses: 4 × 2 = 8.
Square brackets: 10 – 8 = 2.
Curly brackets: 2 + 3 = 5.
Divide: 20 ÷ 5 = 4.

16 / 146

The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?

Explanation:

Let the ten's digit be x and unit's digit be y.

Then, (10x + y) - (10y + x) = 36

 9(x - y) = 36

 x - y = 4.

Explanation:

Let the ten's digit be x and unit's digit be y.

Then, (10x + y) - (10y + x) = 36

 9(x - y) = 36

 x - y = 4.

17 / 146

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?

Explanation:

L.C.M. of 12, 18, 21 30 2 | 12 - 18 - 21 - 30

----------------------------= 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15

----------------------------Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5

Explanation:

L.C.M. of 12, 18, 21 30 2 | 12 - 18 - 21 - 30

----------------------------= 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15

----------------------------Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5

18 / 146

Raju bought a book for ₹ 35.65. He gave ₹ 50 to the shopkeeper. How much money did he get back from the shopkeeper?

19 / 146

252 can be expressed as a product of primes as:

Explanation:
Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Explanation:
Clearly, 252 = 2 x 2 x 3 x 3 x 7.

20 / 146

Which of the following point lies between 0.1 and 0.2?

21 / 146

What is the sum of two consecutive even numbers, the difference of whose squares is 84?

Explanation:

Let the numbers be x and x + 2.

Then, (x + 2)2 - x2 = 84

 4x + 4 = 84

 4x = 80

 x = 20.

 The required sum = x + (x + 2) = 2x + 2 = 42.

Explanation:

Let the numbers be x and x + 2.

Then, (x + 2)2 - x2 = 84

 4x + 4 = 84

 4x = 80

 x = 20.

 The required sum = x + (x + 2) = 2x + 2 = 42.

22 / 146

If 0.75 : x :: 5 : 8, then x is equal to:

Explanation:
(x x 5) = (0.75 x 8)    x = 6 = 1.20
5
Explanation:
(x x 5) = (0.75 x 8)    x = 6 = 1.20
5

23 / 146

If b=6b = 6b=6, solve (b÷2)+10−4(b ÷ 2) + 10 – 4(b÷2)+10−4

Answer

Substitute: (6 ÷ 2) + 10 – 4.
Brackets: 6 ÷ 2 = 3.
Add: 3 + 10 = 13.
Subtract: 13 – 4 = 9.

Answer

Substitute: (6 ÷ 2) + 10 – 4.
Brackets: 6 ÷ 2 = 3.
Add: 3 + 10 = 13.
Subtract: 13 – 4 = 9.

24 / 146

What is the formula for the curved surface area of a regular cylinder?

The formula for the curved surface area of a regular cylinder is 2πrh

The formula for the curved surface area of a regular cylinder is 2πrh

25 / 146

Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.

Explanation:
5% of A + 4% of B = 2  (6% of A + 8% of B)
3
5  A + 4  B = 2 6  A + 8  B
100 100 3 100 100
1  A + 1  B = 1  A + 4  B
20 25 25 75
1 - 1  A = 4 - 1  B
20 25 75 25
1  A = 1  B
100 75
A = 100 = 4 .
B 75 3

 Required ratio = 4 : 3

Explanation:
5% of A + 4% of B = 2  (6% of A + 8% of B)
3
5  A + 4  B = 2 6  A + 8  B
100 100 3 100 100
1  A + 1  B = 1  A + 4  B
20 25 25 75
1 - 1  A = 4 - 1  B
20 25 75 25
1  A = 1  B
100 75
A = 100 = 4 .
B 75 3

 Required ratio = 4 : 3

26 / 146

The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:

Explanation:

Clearly, the numbers are (23 x 13) and (23 x 14).

 Larger number = (23 x 14) = 322.

Explanation:

Clearly, the numbers are (23 x 13) and (23 x 14).

 Larger number = (23 x 14) = 322.

27 / 146

Find the length of the edge of a cube whose surface area is given as 54 cm².

Explanation: The surface area for a cube is given as 

A = 6 (edge)2.

Therefore, upon substituting the value for surface area in the above formula,

(edge)² = 54/ 6 cm2

= 9  cm2

After taking the square root, we get,

edge = 3 cm

Explanation: The surface area for a cube is given as 

A = 6 (edge)2.

Therefore, upon substituting the value for surface area in the above formula,

(edge)² = 54/ 6 cm2

= 9  cm2

After taking the square root, we get,

edge = 3 cm

28 / 146

The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?

Explanation:

Let A = 2k, B = 3k and C = 5k.

A's new salary = 115 of 2k = 115 x 2k = 23k
100 100 10
B's new salary = 110 of 3k = 110 x 3k = 33k
100 100 10
C's new salary = 120 of 5k = 120 x 5k = 6k
100 100
 New ratio 23k : 33k : 6k = 23 : 33 : 60
10 10
Explanation:

Let A = 2k, B = 3k and C = 5k.

A's new salary = 115 of 2k = 115 x 2k = 23k
100 100 10
B's new salary = 110 of 3k = 110 x 3k = 33k
100 100 10
C's new salary = 120 of 5k = 120 x 5k = 6k
100 100
 New ratio 23k : 33k : 6k = 23 : 33 : 60
10 10

29 / 146

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3      x = 11.

 Third integer = x + 4 = 15.

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3      x = 11.

 Third integer = x + 4 = 15.

30 / 146

A student multiplied a number by 3 instead of 5 .
5 3

What is the percentage error in the calculation?

Explanation:

Let the number be x.

Then, error = 5 x - 3 x = 16 x.
3 5 15
Error% = 16x x 3 x 100 % = 64%.
15 5x
Explanation:

Let the number be x.

Then, error = 5 x - 3 x = 16 x.
3 5 15
Error% = 16x x 3 x 100 % = 64%.
15 5x

31 / 146

30 + (8 × 4) – 9

Answer

Brackets: 8 × 4 = 32.
Add: 30 + 32 = 62.
Subtract: 62 – 9 = 53.

Answer

Brackets: 8 × 4 = 32.
Add: 30 + 32 = 62.
Subtract: 62 – 9 = 53.

32 / 146

If m=4m = 4m=4, n=2n = 2n=2, solve (m−n)2+n(m – n)^2 + n(m−n)2+n

Answer

Substitute: (4 – 2)^2 + 2.
Brackets: 4 – 2 = 2.
Power: 22=42^2 = 422=4.
Add: 4 + 2 = 6.

Answer

Substitute: (4 – 2)^2 + 2.
Brackets: 4 – 2 = 2.
Power: 22=42^2 = 422=4.
Add: 4 + 2 = 6.

33 / 146

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

34 / 146

(24 ÷ 4) × 5 – 7

Answer

Brackets: 24 ÷ 4 = 6.
Multiply: 6 × 5 = 30.
Subtract: 30 – 7 = 23.

Answer

Brackets: 24 ÷ 4 = 6.
Multiply: 6 × 5 = 30.
Subtract: 30 – 7 = 23.

35 / 146

The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:

Explanation:

Let the three parts be A, B, C. Then,

A : B = 2 : 3 and B : C = 5 : 8 = 5 x 3 : 8 x 3 = 3 : 24
5 5 5
 A : B : C = 2 : 3 : 24 = 10 : 15 : 24
5
 B = 98 x 15 = 30.
49
Explanation:

Let the three parts be A, B, C. Then,

A : B = 2 : 3 and B : C = 5 : 8 = 5 x 3 : 8 x 3 = 3 : 24
5 5 5
 A : B : C = 2 : 3 : 24 = 10 : 15 : 24
5
 B = 98 x 15 = 30.
49

36 / 146

The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

Explanation:

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7

= 1008 + 7

= 1015

Explanation:

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7

= 1008 + 7

= 1015

37 / 146

Find: 15 × (4 – 1) ÷ 3

Answer:

Brackets: 4 – 1 = 3.
Multiply: 15 × 3 = 45.
Divide: 45 ÷ 3 = 15.

Answer:

Brackets: 4 – 1 = 3.
Multiply: 15 × 3 = 45.
Divide: 45 ÷ 3 = 15.

38 / 146

Calculate: 6 + {8 ÷ [5 – (2 + 1)]}

Solution:

Parentheses: 2 + 1 = 3.
Square brackets: 5 – 3 = 2.
Curly brackets: 8 ÷ 2 = 4.
Add: 6 + 4 = 10.

Solution:

Parentheses: 2 + 1 = 3.
Square brackets: 5 – 3 = 2.
Curly brackets: 8 ÷ 2 = 4.
Add: 6 + 4 = 10.

39 / 146

Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?

Explanation:

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then, 2x + 4000 = 40
3x + 4000 57

 57(2x + 4000) = 40(3x + 4000)

 6x = 68,000

 3x = 34,000

Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.

Explanation:

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then, 2x + 4000 = 40
3x + 4000 57

 57(2x + 4000) = 40(3x + 4000)

 6x = 68,000

 3x = 34,000

Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.

40 / 146

What is the decimal expansion of 5/10?

The correct answer is (a) 0.5.
To find the decimal expansion of a fraction with a denominator of $10$, you move the decimal point of the numerator one place to the left.

Reasoning:

  1. Identify the fraction: $\frac{5}{10}$.
  2. Apply place value: Dividing a number by $10$ shifts its digits one position to the right relative to the decimal point.
  3. Calculate: $5 \div 10 = 0.5$.
In the context of the previous problems, this means the digit $5$ sits in the tenths place.

✅ Answer

The decimal expansion of $\frac{5}{10}$ is 0.5.
The correct answer is (a) 0.5.
To find the decimal expansion of a fraction with a denominator of $10$, you move the decimal point of the numerator one place to the left.

Reasoning:

  1. Identify the fraction: $\frac{5}{10}$.
  2. Apply place value: Dividing a number by $10$ shifts its digits one position to the right relative to the decimal point.
  3. Calculate: $5 \div 10 = 0.5$.
In the context of the previous problems, this means the digit $5$ sits in the tenths place.

✅ Answer

The decimal expansion of $\frac{5}{10}$ is 0.5.

41 / 146

Find the lowest common multiple of 24, 36 and 40.

Explanation:
2 | 24 - 36 - 40
--------------------
2 | 12 - 18 - 20
--------------------
2 | 6 - 9 - 10
-------------------
3 | 3 - 9 - 5
-------------------
| 1 - 3 - 5

L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.
Explanation:
2 | 24 - 36 - 40
--------------------
2 | 12 - 18 - 20
--------------------
2 | 6 - 9 - 10
-------------------
3 | 3 - 9 - 5
-------------------
| 1 - 3 - 5

L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.

42 / 146

Write the following as decimals: “Two ones and five-tenths”.

43 / 146

Which of the following number can be placed in the tens column if the given number is 297.35?

44 / 146

Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

Explanation:

Let the third number be x.

Then, first number = 120% of x = 120x = 6x
100 5
Second number = 150% of x = 150x = 3x
100 2
 Ratio of first two numbers = 6x : 3x = 12x : 15x = 4 : 5.
5 2
Explanation:

Let the third number be x.

Then, first number = 120% of x = 120x = 6x
100 5
Second number = 150% of x = 150x = 3x
100 2
 Ratio of first two numbers = 6x : 3x = 12x : 15x = 4 : 5.
5 2

45 / 146

1 litre = ______ cubic centimeters?

Explanation: The conversion ratio from cubic meter to litres is

1 m3 = 1,000 l

Since 1 m3 = 1000000 cm3

Using the above two conversion ratios, we get

1 l = 1000 cm3

Explanation: The conversion ratio from cubic meter to litres is

1 m3 = 1,000 l

Since 1 m3 = 1000000 cm3

Using the above two conversion ratios, we get

1 l = 1000 cm3

46 / 146

Simplify: (20 ÷ 5) × 2 + 1

Answer:

Brackets first: 20 ÷ 5 = 4.
Multiply: 4 × 2 = 8.
Add: 8 + 1 = 9.

Answer:

Brackets first: 20 ÷ 5 = 4.
Multiply: 4 × 2 = 8.
Add: 8 + 1 = 9.

47 / 146

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point ?

Explanation:

L.C.M. of 252, 308 and 198 = 2772.

So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.

Explanation:

L.C.M. of 252, 308 and 198 = 2772.

So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.

48 / 146

Evaluate: (7 + 5) ÷ (4 – 1)

Solution:

Round brackets: 7 + 5 = 12 and 4 – 1 = 3.
Divide: 12 ÷ 3 = 4.

Solution:

Round brackets: 7 + 5 = 12 and 4 – 1 = 3.
Divide: 12 ÷ 3 = 4.

49 / 146

Find the height of a regular cylinder whose radius is 14 cm and the total surface area is 4342 cm²  is (take pi= 22/7):

Explanation: For a given cylinder, we know that

Total surface area = 2πr (h + r)

Therefore, 

4342= 2 x 22/7 x 14 (h + 14) cm²2 

h = 35.34 cm

Explanation: For a given cylinder, we know that

Total surface area = 2πr (h + r)

Therefore, 

4342= 2 x 22/7 x 14 (h + 14) cm²2 

h = 35.34 cm

50 / 146

32.549 > 32.458 because:

51 / 146

Work out: (8 ÷ 2)^2 – 5

Answer:

Brackets: 8 ÷ 2 = 4.
Power: 42=164^2 = 1642=16.
Subtract: 16 – 5 = 11.

Answer:

Brackets: 8 ÷ 2 = 4.
Power: 42=164^2 = 1642=16.
Subtract: 16 – 5 = 11.

52 / 146

The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

Explanation:

L.C.M. of 6, 9, 15 and 18 is 90.

Let required number be 90k + 4, which is multiple of 7.

Least value of k for which (90k + 4) is divisible by 7 is k = 4.

 Required number = (90 x 4) + 4   = 364.

Explanation:

L.C.M. of 6, 9, 15 and 18 is 90.

Let required number be 90k + 4, which is multiple of 7.

Least value of k for which (90k + 4) is divisible by 7 is k = 4.

 Required number = (90 x 4) + 4   = 364.

53 / 146

In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:

Explanation:
Quantity of milk = 60 x 2 litres = 40 litres.
3

Quantity of water in it = (60- 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be x litres.

Then, milk : water = 40 .
20 + x
Now, 40 = 1
20 + x 2

 20 + x = 80

 x = 60.

 Quantity of water to be added = 60 litres.

Explanation:
Quantity of milk = 60 x 2 litres = 40 litres.
3

Quantity of water in it = (60- 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be x litres.

Then, milk : water = 40 .
20 + x
Now, 40 = 1
20 + x 2

 20 + x = 80

 x = 60.

 Quantity of water to be added = 60 litres.

54 / 146

The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:

Explanation:

Let the numbers 13a and 13b.

Then, 13a x 13b = 2028

 ab = 12.

Now, the co-primes with product 12 are (1, 12) and (3, 4).

[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]

So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).

Clearly, there are 2 such pairs.

Explanation:

Let the numbers 13a and 13b.

Then, 13a x 13b = 2028

 ab = 12.

Now, the co-primes with product 12 are (1, 12) and (3, 4).

[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]

So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).

Clearly, there are 2 such pairs.

55 / 146

Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:

Explanation:

Let the numbers be 3x, 4x and 5x.

Then, their L.C.M. = 60x.

So, 60x = 2400 or x = 40.

 The numbers are (3 x 40), (4 x 40) and (5 x 40).

Hence, required H.C.F. = 40.

Explanation:

Let the numbers be 3x, 4x and 5x.

Then, their L.C.M. = 60x.

So, 60x = 2400 or x = 40.

 The numbers are (3 x 40), (4 x 40) and (5 x 40).

Hence, required H.C.F. = 40.

56 / 146

Find the area of a parallelogram with height and breadth given to be 11 cm and 12  cm, respectively.

Explanation: The formula for the area of a parallelogram is given as

area = base x height

Upon substituting the values for breadth and height, we get

area = 11 x 12  cm2 

= 132 cm2 

Explanation: The formula for the area of a parallelogram is given as

area = base x height

Upon substituting the values for breadth and height, we get

area = 11 x 12  cm2 

= 132 cm2 

57 / 146

In a two-digit, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:

Explanation:

Let the ten's digit be x.

Then, unit's digit = x + 2.

Number = 10x + (x + 2) = 11x + 2.

Sum of digits = x + (x + 2) = 2x + 2.

 (11x + 2)(2x + 2) = 144

 22x2 + 26x - 140 = 0

 11x2 + 13x - 70 = 0

 (x - 2)(11x + 35) = 0

 x = 2.

Hence, required number = 11x + 2 = 24.

Explanation:

Let the ten's digit be x.

Then, unit's digit = x + 2.

Number = 10x + (x + 2) = 11x + 2.

Sum of digits = x + (x + 2) = 2x + 2.

 (11x + 2)(2x + 2) = 144

 22x2 + 26x - 140 = 0

 11x2 + 13x - 70 = 0

 (x - 2)(11x + 35) = 0

 x = 2.

Hence, required number = 11x + 2 = 24.

58 / 146

Which of the following has the most number of divisors?
Explanation:

99 = 1 x 3 x 3 x 11

101 = 1 x 101

176 = 1 x 2 x 2 x 2 x 2 x 11

182 = 1 x 2 x 7 x 13

So, divisors of 99 are 1, 3, 9, 11, 33, .99

Divisors of 101 are 1 and 101

Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176

Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.

Hence, 176 has the most number of divisors.

Explanation:

99 = 1 x 3 x 3 x 11

101 = 1 x 101

176 = 1 x 2 x 2 x 2 x 2 x 11

182 = 1 x 2 x 7 x 13

So, divisors of 99 are 1, 3, 9, 11, 33, .99

Divisors of 101 are 1 and 101

Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176

Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.

Hence, 176 has the most number of divisors.

59 / 146

Evaluate: [9 + (12 ÷ (6 ÷ 3))] – 2

Solution:

Innermost: 6 ÷ 3 = 2.
Next: 12 ÷ 2 = 6.
Square brackets: 9 + 6 = 15.
Subtract: 15 – 2 = 13.

Solution:

Innermost: 6 ÷ 3 = 2.
Next: 12 ÷ 2 = 6.
Square brackets: 9 + 6 = 15.
Subtract: 15 – 2 = 13.

60 / 146

8888 m in Km can be written as:

61 / 146

The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is:

Explanation:

Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.

Explanation:

Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.

62 / 146

Rajeev buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods.

Explanation:
Rebate = 6% of Rs. 6650 = Rs. 6 x 6650 = Rs. 399.
100
Sales tax = 10% of Rs. (6650 - 399) = Rs. 10 x 6251 = Rs. 625.10
100

 Final amount = Rs. (6251 + 625.10) = Rs. 6876.10

Explanation:
Rebate = 6% of Rs. 6650 = Rs. 6 x 6650 = Rs. 399.
100
Sales tax = 10% of Rs. (6650 - 399) = Rs. 10 x 6251 = Rs. 625.10
100

 Final amount = Rs. (6251 + 625.10) = Rs. 6876.10

63 / 146

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

Explanation:
C's 1 day's work = 1 - 1 + 1 = 1 - 7 = 1 .
3 6 8 3 24 24
A's wages : B's wages : C's wages = 1 : 1 : 1 = 4 : 3 : 1.
6 8 24
C's share (for 3 days) = Rs. 3 x 1 x 3200 = Rs. 400.
24
Explanation:
C's 1 day's work = 1 - 1 + 1 = 1 - 7 = 1 .
3 6 8 3 24 24
A's wages : B's wages : C's wages = 1 : 1 : 1 = 4 : 3 : 1.
6 8 24
C's share (for 3 days) = Rs. 3 x 1 x 3200 = Rs. 400.
24

64 / 146

The area of a rhombus is 360 cm²  and one of the diagonals is 12 cm. Find the other diagonal.

Explanation: Because the area of a rhombus is given as,

area = ½ X (product of lengths of the diagonals)

Therefore, we get,

360 = ½ X (12 x diagonal2)  cm2

diagonal2 = 60 cm

Explanation: Because the area of a rhombus is given as,

area = ½ X (product of lengths of the diagonals)

Therefore, we get,

360 = ½ X (12 x diagonal2)  cm2

diagonal2 = 60 cm

65 / 146

A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is:

Explanation:

Let the middle digit be x.

Then, 2x = 10 or x = 5. So, the number is either 253 or 352.

Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.

Hence, required number = 253.

Explanation:

Let the middle digit be x.

Then, 2x = 10 or x = 5. So, the number is either 253 or 352.

Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.

Hence, required number = 253.

66 / 146

In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is  of the number of students of 8 years of age which is 48. What is the total number of students in the school?

Explanation:

Let the number of students be x. Then,

Number of students above 8 years of age = (100 - 20)% of x = 80% of x.

 80% of x = 48 + 2 of 48
3
80 x = 80
100

 x = 100.

Explanation:

Let the number of students be x. Then,

Number of students above 8 years of age = (100 - 20)% of x = 80% of x.

 80% of x = 48 + 2 of 48
3
80 x = 80
100

 x = 100.

67 / 146

A and B together have ₹ 1210. If  of A's amount is equal to  of B's amount, how much amount does B have?

Explanation:
4 A = 2 B
15 5
 A = 2 x 15 B
5 4
 A = 3 B
2
A = 3
B 2

 A : B = 3 : 2.

 B's share = Rs. 1210 x 2 = ₹ 484.
5
Explanation:
4 A = 2 B
15 5
 A = 2 x 15 B
5 4
 A = 3 B
2
A = 3
B 2

 A : B = 3 : 2.

 B's share = Rs. 1210 x 2 = ₹ 484.
5

68 / 146

A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:

Explanation:

Let the ten's digit be x and unit's digit be y.

Then, number = 10x + y.

Number obtained by interchanging the digits = 10y + x.

 (10x + y) + (10y + x) = 11(x + y), which is divisible by 11.

Explanation:

Let the ten's digit be x and unit's digit be y.

Then, number = 10x + y.

Number obtained by interchanging the digits = 10y + x.

 (10x + y) + (10y + x) = 11(x + y), which is divisible by 11.

69 / 146

A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?

Explanation:
Whole work is done by A in ( 20 x 5 ) = 25 days.
4
Now, ( 1 - 4 ) i.e., 1 work is done by A and B in 3 days.
5 5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 .
25 15
Therefore B's 1 day's work = ( 1 - 1 ) = 4 = 2 .
15 25 150 75
So, B alone would do the work in 75 = 37 1 days.
2 2
Explanation:
Whole work is done by A in ( 20 x 5 ) = 25 days.
4
Now, ( 1 - 4 ) i.e., 1 work is done by A and B in 3 days.
5 5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 .
25 15
Therefore B's 1 day's work = ( 1 - 1 ) = 4 = 2 .
15 25 150 75
So, B alone would do the work in 75 = 37 1 days.
2 2

70 / 146

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

 Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

 Required number = (840 x 2 + 3) = 1683.

Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

 Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

 Required number = (840 x 2 + 3) = 1683.

71 / 146

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000
 Required average = 50 % = 5%.
10
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000
 Required average = 50 % = 5%.
10

72 / 146

The fourth proportional to 5, 8, 15 is:

Explanation:

Let the fourth proportional to 5, 8, 15 be x.

Then, 5 : 8 : 15 : x

 5x = (8 x 15)

x = (8 x 15) = 24.
5
Explanation:

Let the fourth proportional to 5, 8, 15 be x.

Then, 5 : 8 : 15 : x

 5x = (8 x 15)

x = (8 x 15) = 24.
5

73 / 146

Evaluate: 9 + 24 ÷ (12 ÷ 4)

Answer:

Innermost brackets: 12 ÷ 4 = 3.
Divide: 24 ÷ 3 = 8.
Add: 9 + 8 = 17.

Answer:

Innermost brackets: 12 ÷ 4 = 3.
Divide: 24 ÷ 3 = 8.
Add: 9 + 8 = 17.

74 / 146

Solve 45−(9÷a)45 – (9 ÷ a)45−(9÷a) when a=3a = 3a=3

Answer

Substitute: 45 – (9 ÷ 3).
Brackets: 9 ÷ 3 = 3.
Subtract: 45 – 3 = 42.

Answer

Substitute: 45 – (9 ÷ 3).
Brackets: 9 ÷ 3 = 3.
Subtract: 45 – 3 = 42.

75 / 146

Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:

Explanation:

Let the numbers be 3x and 5x.

Then, 3x - 9 = 12
5x - 9 23

 23(3x - 9) = 12(5x - 9)

 9x = 99

 x = 11.

 The smaller number = (3 x 11) = 33.

Explanation:

Let the numbers be 3x and 5x.

Then, 3x - 9 = 12
5x - 9 23

 23(3x - 9) = 12(5x - 9)

 9x = 99

 x = 11.

 The smaller number = (3 x 11) = 33.

76 / 146

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

Explanation:

Let the numbers be a and b.

Then, a + b = 55 and ab = 5 x 120 = 600.

 The required sum = 1 + 1 = a + b = 55 = 11
a b ab 600 120
Explanation:

Let the numbers be a and b.

Then, a + b = 55 and ab = 5 x 120 = 600.

 The required sum = 1 + 1 = a + b = 55 = 11
a b ab 600 120

77 / 146

The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:

Explanation:

Let the numbers be a, b and c.

Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.

(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 x 131 = 400.

 (a + b + c) = 400 = 20.

Explanation:

Let the numbers be a, b and c.

Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.

(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 x 131 = 400.

 (a + b + c) = 400 = 20.

78 / 146

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

79 / 146

Calculate: (16 ÷ (8 ÷ 2)) + 1

Solution:

Innermost: 8 ÷ 2 = 4.
Divide: 16 ÷ 4 = 4.
Add: 4 + 1 = 5.

Solution:

Innermost: 8 ÷ 2 = 4.
Divide: 16 ÷ 4 = 4.
Add: 4 + 1 = 5.

80 / 146

14 – 6 ÷ 2 × 3

Answer

Division: 6 ÷ 2 = 3.
Multiply: 3 × 3 = 9.
Subtract: 14 – 9 = 5.

Answer

Division: 6 ÷ 2 = 3.
Multiply: 3 × 3 = 9.
Subtract: 14 – 9 = 5.

81 / 146

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

Required number = (L.C.M. of 12, 15, 20, 54) + 8

= 540 + 8

= 548.

Required number = (L.C.M. of 12, 15, 20, 54) + 8

= 540 + 8

= 548.

82 / 146

Find the radius of a circle whose circumference is given to be 95 cm (take pi= 3.14).

Explanation: We know that the circumference for a circle is given as,

C= 2πr

Substituting the values given in the question, we get

r = 95/ (2 X 3.14) cm

Hence, giving us, 

r = 15.13 cm

Explanation: We know that the circumference for a circle is given as,

C= 2πr

Substituting the values given in the question, we get

r = 95/ (2 X 3.14) cm

Hence, giving us, 

r = 15.13 cm

83 / 146

Find the highest common factor of 36 and 84.

Explanation:

36 = 22 x 32

84 = 22 x 3 x 7

 H.C.F. = 22 x 3 = 12.

Explanation:

36 = 22 x 32

84 = 22 x 3 x 7

 H.C.F. = 22 x 3 = 12.

84 / 146

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:

Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.

Also, the given two products have the middle number in common.

So, middle number = H.C.F. of 551 and 1073 = 29;

First number = 551 = 19;    Third number = 1073 = 37.
29 29

 Required sum = (19 + 29 + 37) = 85.

Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.

Also, the given two products have the middle number in common.

So, middle number = H.C.F. of 551 and 1073 = 29;

First number = 551 = 19;    Third number = 1073 = 37.
29 29

 Required sum = (19 + 29 + 37) = 85.

85 / 146

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:

Explanation:

Number of valid votes = 80% of 7500 = 6000.

 Valid votes polled by other candidate = 45% of 6000

= 45 x 6000 = 2700.
100
Explanation:

Number of valid votes = 80% of 7500 = 6000.

 Valid votes polled by other candidate = 45% of 6000

= 45 x 6000 = 2700.
100

86 / 146

Find the breadth of a cuboid when the volume is given to be 64 m³ for length and height given as 8 m and 2 m, respectively.

Explanation: The volume for a cuboid is given as,

vol = length x breadth x height

Substituting the above-given values and rearranging the equation gives us

breadth = 64/ (8 x 2) m

 = 4 m

Explanation: The volume for a cuboid is given as,

vol = length x breadth x height

Substituting the above-given values and rearranging the equation gives us

breadth = 64/ (8 x 2) m

 = 4 m

87 / 146

A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:

Explanation:
Let the ten's and unit digit be x and 8 respectively.
x
Then, 10x + 8 + 18 = 10 x 8 + x
x x

 10x2 + 8 + 18x = 80 + x2

 9x2 + 18x - 72 = 0

 x2 + 2x - 8 = 0

 (x + 4)(x - 2) = 0

 x = 2.

Explanation:
Let the ten's and unit digit be x and 8 respectively.
x
Then, 10x + 8 + 18 = 10 x 8 + x
x x

 10x2 + 8 + 18x = 80 + x2

 9x2 + 18x - 72 = 0

 x2 + 2x - 8 = 0

 (x + 4)(x - 2) = 0

 x = 2.

88 / 146

What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?

Explanation:

Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.

Number of such number =14

 Required percentage = 14 x 100 % = 20%.
70
Explanation:

Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.

Number of such number =14

 Required percentage = 14 x 100 % = 20%.
70

89 / 146

If Rs. 782 be divided into three parts, proportional to  :  : , then the first part is:

Explanation:

Given ratio =  :  :  = 6 : 8 : 9.

 1st part = Rs. 782 x 6 = Rs. 204
23
Explanation:

Given ratio =  :  :  = 6 : 8 : 9.

 1st part = Rs. 782 x 6 = Rs. 204
23

90 / 146

The area of a trapezium is 1240 m2. The distance between the two pairs of parallel sides is given to be 20 m. If the length of one of the parallel sides is 60 m, find the length of the other parallel side.

Explanation: Using the formula for the area of a trapezium, we get

Area  = ½ h (a+b)

Upon substituting the values given in the above question, 

1240 = ½ x 20 x (60+b) m2

Solving the above equation for b gives us,

b = 64 m

Explanation: Using the formula for the area of a trapezium, we get

Area  = ½ h (a+b)

Upon substituting the values given in the above question, 

1240 = ½ x 20 x (60+b) m2

Solving the above equation for b gives us,

b = 64 m

91 / 146

The number 0.125 can be written as fractions in lowest terms:

92 / 146

If one-third of one-fourth of a number is 15, then three-tenth of that number is:

Explanation:

Let the number be x.

Then, 1 of 1 of x = 15      x = 15 x 3 x 4 = 180.
3 4
So, required number = 3 x 180 = 54.
Explanation:

Let the number be x.

Then, 1 of 1 of x = 15      x = 15 x 3 x 4 = 180.
3 4
So, required number = 3 x 180 = 54.

93 / 146

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

Explanation:

Let the number be x.

Then, x + 17 = 60
x

 x2 + 17x - 60 = 0

 (x + 20)(x - 3) = 0

 x = 3.

Explanation:

Let the number be x.

Then, x + 17 = 60
x

 x2 + 17x - 60 = 0

 (x + 20)(x - 3) = 0

 x = 3.

94 / 146

A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:

Explanation:
(A + B)'s 1 day's work = 1
10
C's 1 day's work = 1
50
(A + B + C)'s 1 day's work = 1 + 1 = 6 = 3 . .... (i)
10 50 50 25

A's 1 day's work = (B + C)'s 1 day's work .... (ii)

From (i) and (ii), we get: 2 x (A's 1 day's work) = 3
25
 A's 1 day's work = 3 .
50
 B's 1 day's work 1 - 3 = 2 = 1 .
10 50 50 25

So, B alone could do the work in 25 days.

Explanation:
(A + B)'s 1 day's work = 1
10
C's 1 day's work = 1
50
(A + B + C)'s 1 day's work = 1 + 1 = 6 = 3 . .... (i)
10 50 50 25

A's 1 day's work = (B + C)'s 1 day's work .... (ii)

From (i) and (ii), we get: 2 x (A's 1 day's work) = 3
25
 A's 1 day's work = 3 .
50
 B's 1 day's work 1 - 3 = 2 = 1 .
10 50 50 25

So, B alone could do the work in 25 days.

95 / 146

If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?

Explanation:
Let 40% of A = 2 B
3
Then, 40A = 2B
100 3
2A = 2B
5 3
A = 2 x 5 = 5
B 3 2 3

 A : B = 5 : 3.

Explanation:
Let 40% of A = 2 B
3
Then, 40A = 2B
100 3
2A = 2B
5 3
A = 2 x 5 = 5
B 3 2 3

 A : B = 5 : 3.

96 / 146

Calculate: 12 – 4 × (6 – 2)

Answer:

First, solve inside the brackets: 6 – 2 = 4.
Then multiply: 4 × 4 = 16.
Subtract: 12 – 16 = -4.

Answer:

First, solve inside the brackets: 6 – 2 = 4.
Then multiply: 4 × 4 = 16.
Subtract: 12 – 16 = -4.

97 / 146

A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets ₹ 1000 more than D, what is B's share?

Explanation:

Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.

Then, 4x - 3x = 1000

 x = 1000.

 B's share = ₹ 2x = ₹ (2 x 1000) = ₹ 2000.

Explanation:

Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.

Then, 4x - 3x = 1000

 x = 1000.

 B's share = ₹ 2x = ₹ (2 x 1000) = ₹ 2000.

98 / 146

A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?

Explanation:
(P + Q + R)'s 1 hour's work = ( 1 + 1 + 1 ) = 37 .
8 10 12 120
Work done by P, Q and R in 2 hours = ( 37 x 2 ) = 37 .
120 60
Remaining work = ( 1 - 37 ) = 23 .
60 60
(Q + R)'s 1 hour's work = ( 1 + 1 ) = 11 .
10 12 60
Now, 11 work is done by Q and R in 1 hour.
60
So, 23 work will be done by Q and R in ( 60 x 23 ) = 23 hours = 2 hours.
60 11 60 11

So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M.

Explanation:
(P + Q + R)'s 1 hour's work = ( 1 + 1 + 1 ) = 37 .
8 10 12 120
Work done by P, Q and R in 2 hours = ( 37 x 2 ) = 37 .
120 60
Remaining work = ( 1 - 37 ) = 23 .
60 60
(Q + R)'s 1 hour's work = ( 1 + 1 ) = 11 .
10 12 60
Now, 11 work is done by Q and R in 1 hour.
60
So, 23 work will be done by Q and R in ( 60 x 23 ) = 23 hours = 2 hours.
60 11 60 11

So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M.

99 / 146

The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?

Explanation:

Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.

Let ten's and unit's digits be 2x and x respectively.

Then, (10 x 2x + x) - (10x + 2x) = 36

 9x = 36

 x = 4.

 Required difference = (2x + x) - (2x - x) = 2x = 8.

Explanation:

Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.

Let ten's and unit's digits be 2x and x respectively.

Then, (10 x 2x + x) - (10x + 2x) = 36

 9x = 36

 x = 4.

 Required difference = (2x + x) - (2x - x) = 2x = 8.

100 / 146

A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?

Explanation:
A's 2 day's work = 1 x 2 = 1 .
20 10
(A + B + C)'s 1 day's work = 1 + 1 + 1 = 6 = 1 .
20 30 60 60 10
Work done in 3 days = 1 + 1 = 1 .
10 10 5
Now, 1 work is done in 3 days.
5

 Whole work will be done in (3 x 5) = 15 days.

Explanation:
A's 2 day's work = 1 x 2 = 1 .
20 10
(A + B + C)'s 1 day's work = 1 + 1 + 1 = 6 = 1 .
20 30 60 60 10
Work done in 3 days = 1 + 1 = 1 .
10 10 5
Now, 1 work is done in 3 days.
5

 Whole work will be done in (3 x 5) = 15 days.

101 / 146

The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

Explanation:
Other number = 11 x 7700 = 308.
275
Explanation:
Other number = 11 x 7700 = 308.
275

102 / 146

Simplify: [25 ÷ (10 – 4)] × 2

Solution:

Round brackets: 10 – 4 = 6.
Square brackets: 25 ÷ 6 ≈ 4.17.
Multiply: 4.17 × 2 ≈ 8.33. (rounded to 2 decimal places)

Solution:

Round brackets: 10 – 4 = 6.
Square brackets: 25 ÷ 6 ≈ 4.17.
Multiply: 4.17 × 2 ≈ 8.33. (rounded to 2 decimal places)

103 / 146

A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:

Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30
B's 1 day's work = 1
90
(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45
 A and B together can do the work in 45 = 22 1 days.
2 2
Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30
B's 1 day's work = 1
90
(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45
 A and B together can do the work in 45 = 22 1 days.
2 2

104 / 146

5.008 can be written in words as:

The correct answer is (d) Five point zero zero eight.

Explanation

When writing a decimal in words using the "point" method, you simply name the whole number, say "point" for the decimal, and then list each digit to the right of the decimal individually:
  • 5 is "Five"
  • . is "point"
  • 0 is "zero"
  • 0 is "zero"
  • 8 is "eight"

Why the others are incorrect:

  • ❌ (a) Five thousand eight: This refers to the whole number 5,008, not the decimal 5.008.
  • ❌ (b) Five point eight: This refers to 5.8, missing the two zeros in the hundredths and thousandths places.
  • ❌ (c) Fifty point eight: This refers to 50.8.
Note: Another mathematically correct way to write this is "Five and eight thousandths", as the 8 is in the thousandths place.
The correct answer is (d) Five point zero zero eight.

Explanation

When writing a decimal in words using the "point" method, you simply name the whole number, say "point" for the decimal, and then list each digit to the right of the decimal individually:
  • 5 is "Five"
  • . is "point"
  • 0 is "zero"
  • 0 is "zero"
  • 8 is "eight"

Why the others are incorrect:

  • ❌ (a) Five thousand eight: This refers to the whole number 5,008, not the decimal 5.008.
  • ❌ (b) Five point eight: This refers to 5.8, missing the two zeros in the hundredths and thousandths places.
  • ❌ (c) Fifty point eight: This refers to 50.8.
Note: Another mathematically correct way to write this is "Five and eight thousandths", as the 8 is in the thousandths place.

105 / 146

What is the place value of 2 in the given decimal 924.75?

The correct answer is (b) tens. [1]
In the decimal number 924.75, the position of each digit relative to the decimal point determines its place value: [2, 3]
  • 9 is in the hundreds place ($900$).
  • ✅ 2 is in the tens place ($20$).
  • 4 is in the ones place ($4$).
  • . (Decimal Point)
  • 7 is in the tenths place ($\frac{7}{10}$ or $0.7$).
  • 5 is in the hundredths place ($\frac{5}{100}$ or $0.05$). [4, 5, 6, 7, 8]

Analysis of Options:

  • ❌ (a) ones: The digit in the ones place is 4.
  • ✅ (b) tens: The digit 2 is the second digit to the left of the decimal point, representing the tens place.
  • ❌ (c) tenth: The digit in the tenths place (first digit to the right of the decimal) is 7.
  • ❌ (d) hundredth: The digit in the hundredths place (second digit to the right of the decimal) is 5. [7, 8, 9, 10, 11]
The correct answer is (b) tens. [1]
In the decimal number 924.75, the position of each digit relative to the decimal point determines its place value: [2, 3]
  • 9 is in the hundreds place ($900$).
  • ✅ 2 is in the tens place ($20$).
  • 4 is in the ones place ($4$).
  • . (Decimal Point)
  • 7 is in the tenths place ($\frac{7}{10}$ or $0.7$).
  • 5 is in the hundredths place ($\frac{5}{100}$ or $0.05$). [4, 5, 6, 7, 8]

Analysis of Options:

  • ❌ (a) ones: The digit in the ones place is 4.
  • ✅ (b) tens: The digit 2 is the second digit to the left of the decimal point, representing the tens place.
  • ❌ (c) tenth: The digit in the tenths place (first digit to the right of the decimal) is 7.
  • ❌ (d) hundredth: The digit in the hundredths place (second digit to the right of the decimal) is 5. [7, 8, 9, 10, 11]

106 / 146

A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:

Explanation:
(A + B + C)'s 1 day's work = 1 ,
4
A's 1 day's work = 1 ,
16
B's 1 day's work = 1 .
12
Therefore C's 1 day's work = 1 - ( 1 + 1 ) = ( 1 - 7 ) = 5 .
4 16 12 4 48 48
So, C alone can do the work in 48 = 9 3 days.
5 5
Explanation:
(A + B + C)'s 1 day's work = 1 ,
4
A's 1 day's work = 1 ,
16
B's 1 day's work = 1 .
12
Therefore C's 1 day's work = 1 - ( 1 + 1 ) = ( 1 - 7 ) = 5 .
4 16 12 4 48 48
So, C alone can do the work in 48 = 9 3 days.
5 5

107 / 146

If 20% of a = b, then b% of 20 is the same as:

Explanation:
20% of a = b     20 a = b.
100
 b% of 20 = b x 20 = 20 a x 1 x 20 = 4 a = 4% of a.
Explanation:
20% of a = b     20 a = b.
100
 b% of 20 = b x 20 = 20 a x 1 x 20 = 4 a = 4% of a.

108 / 146

A cuboidal box has its length, breadth and height given to be 10 cm, 5 cm and 15 cm, respectively. Find the total surface area for the cuboid

Explanation: The formula for total surface area for a cuboid is given as

TSA = 2 x [(l × b) + (b × h) + (h × l)]

Hence, upon substituting the values for length, breadth and height,

TSA = 2 x [(10 x 5)+ (5 x 15) + (15 x 10)]

= 1300 cm2

Explanation: The formula for total surface area for a cuboid is given as

TSA = 2 x [(l × b) + (b × h) + (h × l)]

Hence, upon substituting the values for length, breadth and height,

TSA = 2 x [(10 x 5)+ (5 x 15) + (15 x 10)]

= 1300 cm2

109 / 146

How many cubes with an edge length of 2 cm can fit inside a cuboid with dimensions of length, breadth and height given to be 8 m, 6 m, and 10 m, respectively?

Explanation: Before we calculate the volume of the cuboid, we convert the length, breadth and height into mm from (using the conversion 1 m = 100 cm)

Therefore, 

l = 800 cm

b = 600 cm

h = 1000 cm

Using the formula 

vol = l x b x h

We get the volume of the cuboid as 480000000 cm3

The volume of one of the small cubes is 8 cm3 (using the formula edge x edge x edge)

Hence, the total number of cubes that can fit inside the cuboid is calculated as

tot no. of cubes = 480000000/8

= 60000000

Explanation: Before we calculate the volume of the cuboid, we convert the length, breadth and height into mm from (using the conversion 1 m = 100 cm)

Therefore, 

l = 800 cm

b = 600 cm

h = 1000 cm

Using the formula 

vol = l x b x h

We get the volume of the cuboid as 480000000 cm3

The volume of one of the small cubes is 8 cm3 (using the formula edge x edge x edge)

Hence, the total number of cubes that can fit inside the cuboid is calculated as

tot no. of cubes = 480000000/8

= 60000000

110 / 146

Find the diameter of the circle whose area is given to be 113.04 m2 (take pi = 3.14)

Explanation: The area for a circle is known to be,

area= π r2

And the diameter for a circle is known to be,

d = 2 x r

Using the above two equations and substituting the values given in the question,

113.04 = 3.14 x r2 

r²  = 113.04/ 3.14 m2 

r =  6 m

Hence, 

d = 2 x r

Gives us,

d = 2 x 6 m

  = 12 m

Explanation: The area for a circle is known to be,

area= π r2

And the diameter for a circle is known to be,

d = 2 x r

Using the above two equations and substituting the values given in the question,

113.04 = 3.14 x r2 

r²  = 113.04/ 3.14 m2 

r =  6 m

Hence, 

d = 2 x r

Gives us,

d = 2 x 6 m

  = 12 m

111 / 146

Simplify (4×b−1)÷3(4 × b – 1) ÷ 3(4×b−1)÷3 for b=5b = 5b=5

Answer

Substitute: (4 × 5 – 1) ÷ 3.
Multiply/add: 4 × 5 = 20, 20 – 1 = 19.
Divide: 19 ÷ 3 ≈ 6.33.

Answer

Substitute: (4 × 5 – 1) ÷ 3.
Multiply/add: 4 × 5 = 20, 20 – 1 = 19.
Divide: 19 ÷ 3 ≈ 6.33.

112 / 146

The H.C.F. of 9 , 12 , 18 and 21 is:
10 25 35 40
Explanation:
Required H.C.F. = H.C.F. of 9, 12, 18, 21 = 3
L.C.M. of 10, 25, 35, 40 1400
Explanation:
Required H.C.F. = H.C.F. of 9, 12, 18, 21 = 3
L.C.M. of 10, 25, 35, 40 1400

113 / 146

Which of the following number can be placed in the tenth column if the given number is 297.35?

114 / 146

A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:

Explanation:

Suppose originally he had x apples.

Then, (100 - 40)% of x = 420.

60 x x = 420
100
 x = 420 x 100   = 700.
60
Explanation:

Suppose originally he had x apples.

Then, (100 - 40)% of x = 420.

60 x x = 420
100
 x = 420 x 100   = 700.
60

115 / 146

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

 25(x + 9) = 14(2x + 9)

 3x = 99

 x = 33

So, their marks are 42 and 33.

Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

 25(x + 9) = 14(2x + 9)

 3x = 99

 x = 33

So, their marks are 42 and 33.

116 / 146

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?

Explanation:

L.C.M. of 2, 4, 6, 8, 10, 12 is 120.

So, the bells will toll together after every 120 seconds(2 minutes).

In 30 minutes, they will toll together 30 + 1 = 16 times.
2
Explanation:

L.C.M. of 2, 4, 6, 8, 10, 12 is 120.

So, the bells will toll together after every 120 seconds(2 minutes).

In 30 minutes, they will toll together 30 + 1 = 16 times.
2

117 / 146

A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

Explanation:
A's 1 day's work = 1 ;
15
B's 1 day's work = 1 ;
20
(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60
(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15
Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15
Explanation:
A's 1 day's work = 1 ;
15
B's 1 day's work = 1 ;
20
(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60
(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15
Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

118 / 146

Simplify: 12 – (3 × (7 – 4))

Solution:

Innermost: 7 – 4 = 3.
Multiply: 3 × 3 = 9.
Subtract: 12 – 9 = 3.

Solution:

Innermost: 7 – 4 = 3.
Multiply: 3 × 3 = 9.
Subtract: 12 – 9 = 3.

119 / 146

Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?

Explanation:

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.

Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).

140 x 5x , 150 x 7x and 175 x 8x
100 100 100
 7x, 21x and 14x.
2
 The required ratio = 7x : 21x : 14x
2

 14x : 21x : 28x

 2 : 3 : 4.

Explanation:

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.

Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).

140 x 5x , 150 x 7x and 175 x 8x
100 100 100
 7x, 21x and 14x.
2
 The required ratio = 7x : 21x : 14x
2

 14x : 21x : 28x

 2 : 3 : 4.

120 / 146

The sum of two number is 25 and their difference is 13. Find their product.

Explanation:

Let the numbers be x and y.

Then, x + y = 25 and x - y = 13.

4xy = (x + y)2 - (x- y)2

= (25)2 - (13)2

= (625 - 169)

= 456

 xy = 114.

Explanation:

Let the numbers be x and y.

Then, x + y = 25 and x - y = 13.

4xy = (x + y)2 - (x- y)2

= (25)2 - (13)2

= (625 - 169)

= 456

 xy = 114.

121 / 146

Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

Explanation:

Let the sum paid to Y per week be Rs. z.

Then, z + 120% of z = 550.

 z + 120 z = 550
100
11 z = 550
5
 z = 550 x 5   = 250.
11
Explanation:

Let the sum paid to Y per week be Rs. z.

Then, z + 120% of z = 550.

 z + 120 z = 550
100
11 z = 550
5
 z = 550 x 5   = 250.
11

122 / 146

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

 ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

 Greater number = 111.

Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

 ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

 Greater number = 111.

123 / 146

The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?

Explanation:

Originally, let the number of boys and girls in the college be 7x and 8x respectively.

Their increased number is (120% of 7x) and (110% of 8x).

120 x 7x and 110 x 8x
100 100
42x and 44x
5 5
 The required ratio = 42x : 44x = 21 : 22.
5 5
Explanation:

Originally, let the number of boys and girls in the college be 7x and 8x respectively.

Their increased number is (120% of 7x) and (110% of 8x).

120 x 7x and 110 x 8x
100 100
42x and 44x
5 5
 The required ratio = 42x : 44x = 21 : 22.
5 5

124 / 146

36 ÷ (9 – 3) + 4

Answer

Brackets: 9 – 3 = 6.
Divide: 36 ÷ 6 = 6.
Add: 6 + 4 = 10.

Answer

Brackets: 9 – 3 = 6.
Divide: 36 ÷ 6 = 6.
Add: 6 + 4 = 10.

125 / 146

A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?

Explanation:

Number of runs made by running = 110 - (3 x 4 + 8 x 6)

= 110 - (60)

= 50.

 Required percentage = 50 x 100 % = 45 5 %
110 11
Explanation:

Number of runs made by running = 110 - (3 x 4 + 8 x 6)

= 110 - (60)

= 50.

 Required percentage = 50 x 100 % = 45 5 %
110 11

126 / 146

Two tens and nine tenths in decimal form is given by:

127 / 146

Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?

Explanation:

Let the amount taxable purchases be Rs. x.

Then, 6% of x = 30
100
 x = 30 x 100  = 5.
100 6

 Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70

Explanation:

Let the amount taxable purchases be Rs. x.

Then, 6% of x = 30
100
 x = 30 x 100  = 5.
100 6

 Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70

128 / 146

If a=3a = 3a=3, solve 15+a×(5−2)15 + a × (5 – 2)15+a×(5−2)

Answer

Substitute: 15 + 3 × (5 – 2).
Brackets: 5 – 2 = 3.
Multiply: 3 × 3 = 9.
Add: 15 + 9 = 24.

Answer

Substitute: 15 + 3 × (5 – 2).
Brackets: 5 – 2 = 3.
Multiply: 3 × 3 = 9.
Add: 15 + 9 = 24.

129 / 146

A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?

Explanation:
A's 1 hour's work = 1 ;
4
(B + C)'s 1 hour's work = 1 ;
3
(A + C)'s 1 hour's work = 1 .
2
(A + B + C)'s 1 hour's work = ( 1 + 1 ) = 7 .
4 3 12
B's 1 hour's work = ( 7 - 1 ) = 1 .
12 2 12

Therefore B alone will take 12 hours to do the work.

Explanation:
A's 1 hour's work = 1 ;
4
(B + C)'s 1 hour's work = 1 ;
3
(A + C)'s 1 hour's work = 1 .
2
(A + B + C)'s 1 hour's work = ( 1 + 1 ) = 7 .
4 3 12
B's 1 hour's work = ( 7 - 1 ) = 1 .
12 2 12

Therefore B alone will take 12 hours to do the work.

130 / 146

Find the area of a rhombus whose diagonals are given to be of lengths 6 cm and 7 cm.

Explanation: Since the area of a rhombus is given to be

Area = ½ X (product of lengths of the diagonals)

Therefore, 

area = ½ X (6 X 7)  cm2

=  21 cm2

Explanation: Since the area of a rhombus is given to be

Area = ½ X (product of lengths of the diagonals)

Therefore, 

area = ½ X (6 X 7)  cm2

=  21 cm2

131 / 146

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?

Explanation:

Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.

Then, sum of their values = Rs. 25x + 10 x 2x + 5 x 3x = Rs. 60x
100 100 100 100
60x = 30     x = 30 x 100 = 50.
100 60

Hence, the number of 5 p coins = (3 x 50) = 150.

Explanation:

Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.

Then, sum of their values = Rs. 25x + 10 x 2x + 5 x 3x = Rs. 60x
100 100 100 100
60x = 30     x = 30 x 100 = 50.
100 60

Hence, the number of 5 p coins = (3 x 50) = 150.

132 / 146

Which of the following is smaller?

133 / 146

Reduce 128352 to its lowest terms.
238368

134 / 146

Find the value of 9.756 – 6.28.

135 / 146

Find the value of 35 – 2.54.

136 / 146

4.19 m in cm can be written as:

137 / 146

Find the total surface area for a cube whose volume is given to be 512  m³.

Explanation: The volume for a cube is known to be

vol = edge x edge x edge 

This implies,

512 = (edge)3. m3

Therefore, 

edge = 8 m

Since, the total surface area for a cube is known to be

total surface area = 6 x (edge)2

Upon solving for the square root, we get, 

TSA = 384 cm2

Explanation: The volume for a cube is known to be

vol = edge x edge x edge 

This implies,

512 = (edge)3. m3

Therefore, 

edge = 8 m

Since, the total surface area for a cube is known to be

total surface area = 6 x (edge)2

Upon solving for the square root, we get, 

TSA = 384 cm2

138 / 146

Work out: 5 × [20 – (9 + 2)]

Solution:

Round brackets: 9 + 2 = 11.
Square brackets: 20 – 11 = 9.
Multiply: 5 × 9 = 45.

Solution:

Round brackets: 9 + 2 = 11.
Square brackets: 20 – 11 = 9.
Multiply: 5 × 9 = 45.

139 / 146

If A = x% of y and B = y% of x, then which of the following is true?

Explanation:
x% of y = x x y = y x x = y% of x
100 100

 A = B.

Explanation:
x% of y = x x y = y x x = y% of x
100 100

 A = B.

140 / 146

137 + 5/100 can be written in the decimal form as:

141 / 146

Find the perimeter of the largest circle that can fit inside a square with the side 7cm (take pi = 22/7).

Explanation: Given, that the side of the square is 7cm

Hence, the diameter of the largest circle to fit inside the square, d = 7 cm

This implies that radius, r = 7/2 cm = 3.5 cm

Using the formula for circumference, 

C = 2πr

We get,

C = 2 x 22/7 x 3.5 cm

= 22 cm

Explanation: Given, that the side of the square is 7cm

Hence, the diameter of the largest circle to fit inside the square, d = 7 cm

This implies that radius, r = 7/2 cm = 3.5 cm

Using the formula for circumference, 

C = 2πr

We get,

C = 2 x 22/7 x 3.5 cm

= 22 cm

142 / 146

The sum of 0.007 + 8.5 + 30.08 is:

143 / 146

The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:

Explanation:

Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.

So, the numbers 12 and 16.

L.C.M. of 12 and 16 = 48.

Explanation:

Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.

So, the numbers 12 and 16.

L.C.M. of 12 and 16 = 48.

144 / 146

Which of the following fraction is the largest ?

Explanation:

L.C.M. of 8, 16, 40 and 80 = 80.

7 = 70 ; 13 = 65 ; 31 = 62
8 80 16 80 40 80
Since, 70 > 65 > 63 > 62 , so 7 > 13 > 63 > 31
80 80 80 80 8 16 80 40
So, 7 is the largest.
8
Explanation:

L.C.M. of 8, 16, 40 and 80 = 80.

7 = 70 ; 13 = 65 ; 31 = 62
8 80 16 80 40 80
Since, 70 > 65 > 63 > 62 , so 7 > 13 > 63 > 31
80 80 80 80 8 16 80 40
So, 7 is the largest.
8

145 / 146

600 + 2 + 8/10 can be written in decimal form as:

The correct answer is (b) 602.8.

1. Add whole numbers

First, combine the whole number parts:
$$600 + 2 = 602$$

2. Convert the fraction

Convert the fraction $\frac{8}{10}$ into its decimal equivalent:
$$\frac{8}{10} = 0.8$$

3. Combine both parts

Add the whole number and the decimal together:
602 + 0.8 = 602.8
The correct answer is (b) 602.8.

1. Add whole numbers

First, combine the whole number parts:
$$600 + 2 = 602$$

2. Convert the fraction

Convert the fraction $\frac{8}{10}$ into its decimal equivalent:
$$\frac{8}{10} = 0.8$$

3. Combine both parts

Add the whole number and the decimal together:
602 + 0.8 = 602.8

146 / 146

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2
Solving these two equations, we get : x = 1 and y = 1 .
100 200
(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .
100 200 4

 15 men and 20 boys can do the work in 4 days.

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2
Solving these two equations, we get : x = 1 and y = 1 .
100 200
(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .
100 200 4

 15 men and 20 boys can do the work in 4 days.

Your score is

The average score is 2%

LinkedIn Facebook
0%

Please rate this quiz

Thank You

Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut elit tellus, luctus nec ullamcorper mattis, pulvinar dapibus leo.

Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut elit tellus, luctus nec ullamcorper mattis, pulvinar dapibus leo.

Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut elit tellus, luctus nec ullamcorper mattis, pulvinar dapibus leo.

Share
  • Facebook

Sidebar

Ask A Question

Stats

  • Questions 21
  • Answers 71
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Admin

    How to approach applying for a job at a company ...

    • 7 Answers
  • Admin

    What is a programmer’s life like?

    • 5 Answers
  • Admin

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Martin Hope
    Martin Hope added an answer They might be as confused as to why you keep… April 19, 2018 at 2:07 am
  • Marko Smith
    Marko Smith added an answer I have never heard a British person EVER call a… April 19, 2018 at 2:07 am
  • Barry Carter
    Barry Carter added an answer Calling a bread roll a “biscuit” really takes the biscuit.… April 19, 2018 at 2:07 am

Top Members

Admin

Admin

  • 21 Questions
  • 2 Points

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Explore

  • Discussion
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • Buy Theme

Footer

© 2021 Discy. All Rights Reserved
With Love by 2code